Mixture and Allegations Problem

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Mixture and Allegations Problem

by kanika123 » Wed Jul 31, 2013 4:26 am
A merchant has 100 lbs of sugar, part of which he sells at 7% profit and the rest at 17% profit. He gains 10 % on the whole. Find how much is sold at 7% profit?


A. 70 lbs

B. 40 lbs

C. 30 lbs

D. 50 lbs

E. 60 lb

How to solve quickly?
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by sparkles3144 » Wed Jul 31, 2013 5:15 am
Let's say price per lbs is $10

7% profit over $10 is 10.7
A merchant bought x lbs at $10.7

17% profit over $10 is 11.7
A merchant bought y lbs at $11.7

10% profit over $10 is 11
A merchant bought (x+y) lbs at $11

10.7(X) + 11.7(y) = 11(x+y)

10.7(X) + 11.7(y) = 11x + 11y
0.7(y) = 0.3 x

Only possible values here would be x = 70 and y = 30

So, the answer is A

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by Brent@GMATPrepNow » Wed Jul 31, 2013 7:07 am
kanika123 wrote:A merchant has 100 lbs of sugar, part of which he sells at 7% profit and the rest at 17% profit. He gains 10 % on the whole. Find how much is sold at 7% profit?


A. 70 lbs

B. 40 lbs

C. 30 lbs

D. 50 lbs

E. 60 lb

How to solve quickly?
Here's a reasonably fast approach.
First consider what would happen if half sold for a 7% profit, and the other half sold for a 17% profit.
The result would be a profit that's midway between 7% and 17%. In other words, we'd have a 12% profit.
HOWEVER, the question tells us that we get only a 10% profit.
So, we must have sold more than half of the sugar at the lower 7% profit.
We can now ELIMINATE B, C and D.

At this point, we can test either of the two remaining answer choices (A or E). It doesn't matter which one we test. If the one we test works, we're done. If it doesn't work, we're still done, because we know the other answer is correct.

Let's test E (60 lbs sold at a 7% profit)
So, 60 out of 100 lbs sold at 7%, and 40 out of 100 lbs sold at 17%
We'll use the formula:
Weighted average = (group A proportion)(group A average) + (group B proportion)(group B average)
Weighted average = (0.6)(7) + (0.4)(17)
= 4.2 + 6.8
= 11
So, this scenario would result in a 11% profit. We want an 10% profit, so ELIMINATE E.

By the process of elimination, the correct answer is A

If you're interested, we have a free video on weighted averages: https://www.gmatprepnow.com/module/gmat- ... ics?id=805

Cheers,
Brent
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by Brent@GMATPrepNow » Wed Jul 31, 2013 7:18 am
Looks like my response got posted twice.
Deleted this one.

Cheers,
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Last edited by Brent@GMATPrepNow on Wed Jul 31, 2013 7:21 am, edited 1 time in total.
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by Brent@GMATPrepNow » Wed Jul 31, 2013 7:20 am
kanika123 wrote:A merchant has 100 lbs of sugar, part of which he sells at 7% profit and the rest at 17% profit. He gains 10 % on the whole. Find how much is sold at 7% profit?


A. 70 lbs

B. 40 lbs

C. 30 lbs

D. 50 lbs

E. 60 lb

How to solve quickly?
Alternatively, we can recognize that there are 10 percentage points between 7% and 17%
So, if the proportions are 50-50, then the resulting percent profit will be halfway between 7% and 17%. In other words, the result will be a 12% profit.

If the proportions are 60-40 (that is 60 lbs sold at 7%, and 40 lbs sold at 17%, then the resulting percent profit will be 4 percentage points away from 7%, and 6 percentage points away from 17%. In other words, the result will be an 11% profit.

If the proportions are 70-30 (that is 70 lbs sold at 7%, and 30 lbs sold at 17%, then the resulting percent profit will be 3 percentage points away from 7%, and 7 percentage points away from 17%. In other words, the result will be a 10% profit. BINGO!

Cheers,
Brent
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by GMATGuruNY » Wed Jul 31, 2013 1:23 pm
kanika123 wrote:A merchant has 100 lbs of sugar, part of which he sells at 7% profit and the rest at 17% profit. He gains 10 % on the whole. Find how much is sold at 7% profit?


A. 70 lbs

B. 40 lbs

C. 30 lbs

D. 50 lbs

E. 60 lb

How to solve quickly?
Profit earned by portion A = 7%.
Profit earned by portion B = 17%.
Profit earned by the MIXTURE of A and B = 10%.

To determine the ratio of A to B, use ALLIGATION -- a very efficient way to handle mixture problems.

Step 1: Plot the 3 percentages on a number line, with the percentages for A and B (7% and 17%) on the ends and the percentage for the mixture (10%) in the middle.
A 7---------10----------17 B

Step 2: Calculate the distances between the percentages.
A 7----3----10----7----17 B

Step 3: Determine the ratio in the mixture.
The required ratio of A to B is the RECIPROCAL of the distances in red.
A:B = 7:3 = 70:30.

Thus, of the 100 pounds of sugar:
A = 70 pounds
B = 30 pounds.

The correct answer is A.

Other alligation problems:
https://www.beatthegmat.com/mixture-prob ... tml#593241
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by [email protected] » Wed Jul 31, 2013 2:00 pm
Hi kanika123,

Each of the various approaches listed here is valid (I think that TESTing the answers would be fastest for most people), but you could also solve this problem using algebra (it's called "system math").

Since we don't know what sugar costs, I'm going to say that sugar costs $1 per pound. So we have $100 worth of sugar and we want a 10% profit (so we're looking for an increase of $10). Now we can create 2 equations:

X = the number of pounds sold at 7% profit
Y = the number of pounds sold at 17% profit

X + Y = 100
.07X + .17Y = $10

Since the question is asking for X, we should isolate and eliminate the Y...

Y = 100 - X

Now substitute in to the second equation:

.07X + .17(100 - X) = 10
.07X +17 - .17X = 10

Combine like terms:
7 - .1X = 0
7 = .1X
70 = X

Final Answer: A

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by Dicky John williams » Thu Jan 26, 2017 9:07 am
Instead Plug In The Answers....

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by [email protected] » Thu Jan 26, 2017 9:30 am
Hi Dicky John williams,

TESTing THE ANSWERS is a perfect approach for this question - and that's exactly what Brent did (he just used a bit of logic to eliminate a few of the answers first).

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by Matt@VeritasPrep » Wed Feb 01, 2017 6:10 pm
Plugging in the answers is fine, but the algebra is so simple that it's pretty handy to know:

.07*x + .17*(100 - x) = .10 * 100

so

.07x + 17 - .17x = 10

7 = .1x

x = 70