If two resistors, A(R1) and B(R2) stand in parallel with eac

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If two resistors, A(R1) and B(R2) stand in parallel with each other in electrical wire, the total resistor appears as R1R2/(R1+R2). If three resistors, A(R1), B(R2), and C(2R2) stand in parallel in electrical wire, what is the ratio of the resistors' sum of A and C to the resistors' sum of A and B?

A. 2(R1+R2):(R1+2R2)
B. (R1+R2):(R1+2R2)
C. (2R1+R2):(R1+2R2)
D. 2(R1+R2):(2R1+R2)
E. 2(R1-R2):(R1+2R2)


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by Max@Math Revolution » Wed Jan 20, 2016 9:00 pm
If two resistors, A(R1) and B(R2) stand in parallel with each other in electrical wire, the total resistor appears as R1R2/(R1+R2). If three resistors, A(R1), B(R2), and C(2R2) stand in parallel in electrical wire, what is the ratio of the resistors' sum of A and C to the resistors' sum of A and B?

A. 2(R1+R2):(R1+2R2)
B. (R1+R2):(R1+2R2)
C. (2R1+R2):(R1+2R2)
D. 2(R1+R2):(2R1+R2)
E. 2(R1-R2):(R1+2R2)


the resistors' sum of A and C to the resistors' sum of A and B
=R1*2R2/(R1+2R2):R1*R2/(R1+R2)= 2/(R1+2R2):1/(R1+R2)= 2(R1+R2):(R1+2R2). Therefore, the answer is A.