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Probability Qstn!!

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Probability Qstn!!

by AWR83 » Mon Jan 05, 2009 6:18 am
Patrons at a certain restaurant can select two of three appetizers--fruit, soup, and salad--along with two of three vegetables--carrots, squash, and peas. What is the statistical probability that any patron will select fruit, salad, squash, and peas?

Would someone please explain the answer?
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by Brent@GMATPrepNow » Mon Jan 05, 2009 8:37 am
First determine the denominator - the number of possible outcomes.
Total outcomes = 3C2 X 3C2 = 9

Then determine the numerator - number outcomes favorable to the condition of ordering fruit, salad, squash, and peas.
There is only 1 way to select fruit, salad, squash, and peas.

So, the probability = 1/9
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by AWR83 » Tue Jan 06, 2009 7:15 am
Dear Brent,

Thanks for your help. Act i would appreciate if you would explain the logic behind the answer, and whether all probability questions need to be solved by combination? and whether i might need to use permutation in such questions?

Finally, please advise if there's an alternative way of solving the problem.

Thanks, but my exam is tomorrow and im abit anxious.

regards,
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by logitech » Tue Jan 06, 2009 9:12 am
AWR83 wrote:Dear Brent,

Thanks for your help. Act i would appreciate if you would explain the logic behind the answer, and whether all probability questions need to be solved by combination? and whether i might need to use permutation in such questions?

Finally, please advise if there's an alternative way of solving the problem.

Thanks, but my exam is tomorrow and im abit anxious.

regards,
Good luck! Go kick some GMAT ass!
LGTCH
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