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mlane25269
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Having some trouble understading the logic behind this question. OA is C but I picked E.
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Not sure of the answer but here is my attempt.
Stmt 1 tells us the avg age of x and y committees
ie. 25.7 and 29.3. cant find the size of x, y or z committees.
So not sufficient.
Stmt 2 tells us the avg age of committee z: 26.6
insufficient.
Lets combine.
Lets assume that both x and y committees have equal number of ppl.
So if we combine such a committe, the avg of new committee should have the avg age = avg of x and y
ie avg age of z should have been (25.7 + 29.3)/2 = 28
But the avg age of z is given to be 26.6. This can only happen if number of ppl in committee x is > number of ppl in y.
Picture this problem as a see-saw with one end having x ppl each aged 25.7 yrs; other end has y ppl, each age is 29.3.
If y > x then see-saw tilts towards y. else it tilts towards x.
Ht Helps
