SammyJaggi wrote:Pipe A can fill a pool in 5 days and pipe B can fill the pool in 3 days .if they start working together at same time,how long(in hours) will it take to fill the pool. if pipe B stops working after a DAy??
Pipe A can fill pool in 5 days
In one day Pipe A can fill = 1/5 = 3/15 (multiply by 3 on Nr and Dr)
Similarly,
In one day Pipe B can fill = 1/3 = 5/15 (multiply by 3 on Nr and Dr)
Together in one day they can fill = 3/15 + 5/15 = 8/15 of pool....
Remaining = 1-8/15 = 7/15
Since Pipe B stops working after 1 day, Pipe A has to fill 7/15 of pool alone (awwww....Poor Pipe A)
So Pipe A will take = (7/15)/(3/15) = 7/3 Days
So total no. of days req to fill the pool is = 1 + 7/3 = 10/3 Days
Remember, We have to find no. of hours....not no. of days..(multiply by 24)
So, No. of hours =
80Hrs
