BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

boat race- opposite

Expert replies
by coolgirl26 » Sun Apr 19, 2009 12:39 pm
From starting point in boat race

1 competitor start to sail north at 1.6 km/h

other competitor sails west at 1.2 Km/ h

What is distance in Km between the two competitors after 5 hours


Can someone help

answer is 10


D= R*T??
Join the discussion
Source: — Problem Solving |

by DanaJ » Sun Apr 19, 2009 1:34 pm
See picture for details.

Say x = distance covered by the guy who went north. x will be 1.6 * 5.
y = distance covered by the guy who went west. y will be 1.2 * 5.

Notice that the distances form a right triangle, so the distance you're looking for is the hypotenuse of this triangle (say d).

d^2 = x^2 + y^2

d^2 = (1.6*5)^2 + (1.2*5)^2 = 5^2 (1.6^2 + 1.2*2) = 5^2 * 0.4^2 * (4^2 + 3^2) = 5^2 * 0.4^2 * 5^2

This means that d = 5*5*0.4 = 10.
Attachments
Untitled.jpg
Join the discussion

by vittalgmat » Sun Apr 19, 2009 5:38 pm
Nice job Dana!!.

I got the same answer...

The key takeaway is to apply the d= rt formula to find the distance travelled by both the boats. Then use the Pythagoras theorem to find the length hypotenuse.
Join the discussion