BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

boat race- opposite

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 71
Joined: Tue Mar 03, 2009 1:24 pm
by coolgirl26 » Sun Apr 19, 2009 12:39 pm
From starting point in boat race

1 competitor start to sail north at 1.6 km/h

other competitor sails west at 1.2 Km/ h

What is distance in Km between the two competitors after 5 hours


Can someone help

answer is 10


D= R*T??
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Site Admin
Posts: 2567
Joined: Thu Jan 01, 2009 10:05 amFollowed by: 550 members
Thanked: 712 times
GMAT Score:770

by DanaJ » Sun Apr 19, 2009 1:34 pm
See picture for details.

Say x = distance covered by the guy who went north. x will be 1.6 * 5.
y = distance covered by the guy who went west. y will be 1.2 * 5.

Notice that the distances form a right triangle, so the distance you're looking for is the hypotenuse of this triangle (say d).

d^2 = x^2 + y^2

d^2 = (1.6*5)^2 + (1.2*5)^2 = 5^2 (1.6^2 + 1.2*2) = 5^2 * 0.4^2 * (4^2 + 3^2) = 5^2 * 0.4^2 * 5^2

This means that d = 5*5*0.4 = 10.
Attachments
Untitled.jpg
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 621
Joined: Wed Apr 09, 2008 7:13 pmFollowed by: 4 members
Thanked: 33 times

by vittalgmat » Sun Apr 19, 2009 5:38 pm
Nice job Dana!!.

I got the same answer...

The key takeaway is to apply the d= rt formula to find the distance travelled by both the boats. Then use the Pythagoras theorem to find the length hypotenuse.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1