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Source: — Problem Solving |
Junior | Next Rank: 30 Posts
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ans

by smashinonions » Sun Jun 22, 2008 6:25 pm
Let X1, X2, X3 be the 3 readings so,


X1 + X2 + X3 / 3 = 8

or X 1 + X2 + X3 = 24

so as the range is from 0- 10

to find the min qty measured, we maximize the remaining two i.e

X1 (assuming to be smallest) = 24 - (X2 + X3)
= 24 - (10 + 10) [ 10 being the max value that the meter can read)
= 4
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by mlane25269 » Tue Jun 24, 2008 9:36 pm
ok that makes sense! thank you!

is it possible to solve this problem by backsolving and if so how would I backsolve? Or is it easier/quicker just to solve algebraically like in your example above?
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