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1000 PS - Question 15

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Junior | Next Rank: 30 Posts
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1000 PS - Question 15

by Carol » Tue Jun 24, 2008 4:50 am
If n is an integer


n = 2•3•5•7•11•13 / 77k

then which of the following could be the value of k?

(A) 22
(B) 26
(C) 35
(D) 54
(E) 60



Please post your answers and explanations. thx[/list][/quote]
Last edited by Carol on Wed Jun 25, 2008 12:44 am, edited 2 times in total.
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by vcb » Tue Jun 24, 2008 8:36 am
hmm..not sure if there's a typo..did u mean (blahblah)/(77*k) or 77*k*k?
Assuming 77*k, i guess the answer should be 26. 77's factors are 11 and 7.
So, after reducing, we have the fraction as 2*3*5*9*13/k.
Out of the given options, only 26 can be reduced as 2*13...
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by Carol » Tue Jun 24, 2008 8:45 am
that's it. Thank you vcb :wink:
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by visheshsatyam » Tue Jun 24, 2008 9:13 am
I think the question is mis-written, it does nto have a 9 list.

Because if 9 is there then D) 54 also gets applicable as 2*3*9 = 54 and hence n is integer.

Thanks
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Junior | Next Rank: 30 Posts
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by Carol » Wed Jun 25, 2008 12:48 am
thank you visheshsatyam and vcb. There was only one K, and the integer 9 was not inclueded!! :oops: thank you for noticing me!

And thank you for answering and posting your explanations!
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