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Need help explaining this math problem...

by thp510 » Mon Sep 27, 2010 8:37 pm
Quick question:

If an "anglet" is defined as 1 percent of 1 degree, how many anglets are in a circle?

a) 0.36
b) 3.6
c) 360
d) 3600
e) 36000

How I tried to solve it:
1 percent of 1 degree is .01
So I just took .01 and multiplied it to 360 to get 3.6, however this answer is wrong.

Book answer: If an "anglet" is one percent of a degree, then there are 100 anglets in each degree. Since there are 360 degrees in a circle, there are 100x360 or 36,000 anglets in a circle.

Question: I'm not following the book answer here. Where did they get the assumption that a "full" degree = 100?

Thanks
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by Rahul@gurome » Mon Sep 27, 2010 8:48 pm
Solution:
1 anglet is (1/100)* 1 degree =1/100 degree.
So 1 degree is 1 * 100 = 100 anglets.
A circle has 360 degrees.
So A circle has 360 * 100 = 36,000 anglets.

I don't think the book answer is assuming that a ''full" degree is 100.
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by frank1 » Tue Sep 28, 2010 12:38 am
i think i got this question in the pratice test ...may be kaplan i guess
and that is the exact question i asked (with myself) when i saw the explanation....
Where did they get the assumption that a "full" degree = 100?
i never knew that...
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by sanju09 » Tue Sep 28, 2010 4:10 am
tomhpae wrote:Quick question:

If an "anglet" is defined as 1 percent of 1 degree, how many anglets are in a circle?

a) 0.36
b) 3.6
c) 360
d) 3600
e) 36000

How I tried to solve it:
1 percent of 1 degree is .01
So I just took .01 and multiplied it to 360 to get 3.6, however this answer is wrong.

Book answer: If an "anglet" is one percent of a degree, then there are 100 anglets in each degree. Since there are 360 degrees in a circle, there are 100x360 or 36,000 anglets in a circle.

Question: I'm not following the book answer here. Where did they get the assumption that a "full" degree = 100?

Thanks
Do you agree that there are 100 anglets in each degree? Fine, now a circle has 360 degrees subtend at its center, agreed? Fine again, hence there are 360 × 100 = 36000 anglets to it. You see, the ages old unitary method, still alive.
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