Here, using the geometric progression formula may come in handy.knight247 wrote:If the first term of a geometric progression is 1/32 and 11th term is 32, what is the 6th term?
Don't have an OA or the answer choices. Detailed explanations would be appreciated. Thanks
Gn = G1[r^(n-1)], Where, Gn= the nth. term
r= common ratio, G1= the first term
n= the total number of terms under consideration.
Accordingly,
G11 = G1[r^10]
32 = [1/32][r^10]
32 * 32 = r^10
2^5 *2^5 = r^10
2^10 = r^10
r=2
Hence, G6= G1[r^5]
= [1/32][2^5]
= 1.
Therefore, the answer is 1.
