BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

x,y, z

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

x,y, z

by tohellandback » Tue Aug 11, 2009 12:38 am
If xyz ≠ 0, is x (y + z) ≥ 0?


1) |y + z| = |y| + |z|
2) |x + y| = |x| + |y|

OA later
The powers of two are bloody impolite!!
Top
Source: — Data Sufficiency |
Legendary Member
Posts: 876
Joined: Thu Apr 10, 2008 8:14 am
Thanked: 13 times

Re: x,y, z

by ketkoag » Tue Aug 11, 2009 1:06 am
tohellandback wrote:If xyz ≠ 0, is x (y + z) ≥ 0?


1) |y + z| = |y| + |z|
2) |x + y| = |x| + |y|

OA later
IMO C coz if we take either statement then both y an z or x and y will have the same sign.. and hence we don't know what could be the sign of x(y + z).

but if we take both the statements then we know that x, y, z should have the same sign and then we know that x(y+z)>0..
hence C..
Top
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

Re: x,y, z

by tohellandback » Tue Aug 11, 2009 1:11 am
ketkoag wrote:
tohellandback wrote:If xyz ≠ 0, is x (y + z) ≥ 0?


1) |y + z| = |y| + |z|
2) |x + y| = |x| + |y|

OA later
IMO C coz if we take either statement then both y an z or x and y will have the same sign.. and hence we don't know what could be the sign of x(y + z).

but if we take both the statements then we know that x, y, z should have the same sign and then we know that x(y+z)>0..
hence C..
could you elaborate the statement in bold?
The powers of two are bloody impolite!!
Top
Master | Next Rank: 500 Posts
Posts: 138
Joined: Mon Mar 02, 2009 12:02 pm
Thanked: 15 times

Re: x,y, z

by life is a test » Tue Aug 11, 2009 6:51 am
1) |y + z| = |y| + |z| --> this implies that both y and z are positive.
e.g. if y=1 and z=-2 then |(+1) + (-2)| = -1 but |+1| + |-2| = 3 so y and z must both be positive for the eqn to hold. This however, still doesn't tell us about x (it couldn be +ve or -ve, all we know about z form the given info is that is is non-zero.

2) |x + y| = |x| + |y|--> for similar reasons as in 1), x and y must both be positive byt we don't know about z (it can be positive or negative)

1) and 2) together, we know that x, y and z are positive hence x(y+z) must be >0.
Top
Master | Next Rank: 500 Posts
Posts: 116
Joined: Fri Feb 20, 2009 9:26 am
Location: New Jersey
Thanked: 7 times
GMAT Score:660

Re: x,y, z

by Sher1 » Fri Aug 14, 2009 3:22 pm
life is a test wrote:1) |y + z| = |y| + |z| --> this implies that both y and z are positive.
e.g. if y=1 and z=-2 then |(+1) + (-2)| = -1 but |+1| + |-2| = 3 so y and z must both be positive for the eqn to hold. This however, still doesn't tell us about x (it couldn be +ve or -ve, all we know about z form the given info is that is is non-zero.

2) |x + y| = |x| + |y|--> for similar reasons as in 1), x and y must both be positive byt we don't know about z (it can be positive or negative)

1) and 2) together, we know that x, y and z are positive hence x(y+z) must be >0.
I dont think the equations imply they are both positive.
Top
Master | Next Rank: 500 Posts
Posts: 117
Joined: Wed May 13, 2009 7:41 am
Thanked: 5 times

IMHO

by kc_raj » Fri Aug 14, 2009 7:03 pm
IMHO C,

for first to be true both y, z has to be same sign, but x could be any sign and magnitude so not suff.

similarily for second to be true both x, y has to be same sign, but z could be any sign and mag so not suff,

combined x, y, z has to be same sign, either all positive or all neg, either way x(y+z)>=0

so C
Top
Senior | Next Rank: 100 Posts
Posts: 87
Joined: Sat Feb 28, 2009 7:01 am
Location: India
Thanked: 2 times

by imhimanshu » Sun Aug 16, 2009 5:36 am
wots the OA?
Top
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

by tohellandback » Sun Aug 16, 2009 5:43 am
OA is C
The powers of two are bloody impolite!!
Top
Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Wed Nov 26, 2008 9:24 am

by lazyfox » Tue Aug 25, 2009 9:56 am
|y + z| = |y| + |z| --> this implies that both y and z are positive.
e.g. if y=1 and z=-2 then |(+1) + (-2)| = -1 but |+1| + |-2| = 3 so y and z must both be positive for the eqn to hold. This however, still doesn't tell us about x (it couldn be +ve or -ve, all we know about z form the given info is that is is non-zero.


****************************************************
The statement implies that both y and z have same signs: both positive or both negative.

|4+5| = |4| + |5|
|-4-5|= |-4|+|-5|[[/spoiler]
Top
Post new topic Post Reply
• Page 1 of 1