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GMATPrep - exponents again

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Source: — Problem Solving |
Junior | Next Rank: 30 Posts
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by envyk10 » Wed May 09, 2007 11:20 am
I guess splitting 288 into its factors would help and since you are looking for powers of 2 and 3 => 288 = (2^5)X(3^2)

Therefore, 2^x-1 = 16 & 3^y-2 = 1

Ans 16
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by bww » Wed May 09, 2007 6:07 pm
that's right. with these types of questions, you always want to break down the number into its prime factors. in this case, 2^5 and 3^2 (from 2X2X2X2X2X3X3).
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by Cybermusings » Thu May 10, 2007 2:51 am
2^5 * 3^2 = 288
Hence x = 5 and y = 2
So 2^x-1 = 2^4
and 2^y-2 = 2^0 = 1
So answer becomes 2^4 * 1 = 16
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by chitoshia » Thu May 10, 2007 4:16 am
z^(m-n) = (z^m)/(z^n)

That means

288/(2X3^2)

=16

Hence A
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