Rastis wrote:If y is not equal to 4, x is not equal to 0, and (y^2 - 16)/3x = (y - 4)/6, then in terms of x, y equals:
a) (x + 8)/2
b) (x - 8)/2
c) -3x/2
d) (-3x + 8)/2
e) (3x - 8)/2
Let y=0.
Substituting y=0 into (y² - 16)/3x = (y-4)/6, we get:
-16/3x = -4/6
-16/3x = -2/3
-48 = -6x
x=8.
The question stem asks for the value of y=0. This is our target.
Now plug x=8 into the answers to see which yields our target of 0.
Only
B works:
(x-8)/2 = (8-8)/2 = 0.
The correct answer is
B.
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