if n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is
a.6
b.12
c.24
d.36
e.48
a.6
b.12
c.24
d.36
e.48
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n² must be divisible by 72.sanaa.rizwan wrote:if n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is
a.6
b.12
c.24
d.36
e.48
Let us assume, n² = 72k = (2³)*(3²)*k, where k is some positive integer.sanaa.rizwan wrote:if n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is
From the question, How do we know that we have to find the MINIMUM value of n ?sanaa.rizwan wrote:if n is a positive integer and n^2 is divisible by 72, then the largest positive integer that must divide n is
a.6
b.12
c.24
d.36
e.48
Because we can always make n sufficiently large such that all the options (even numbers larger than the provided options) will divide n.gughanbose wrote:From the question, How do we know that we have to find the MINIMUM value of n ?
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