Ratio of two numbers x and y is 3:5. If x is increased by

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Ratio of two numbers x and y is 3:5. If x is increased by 20% and y is increased by 8 then the new ratio becomes 2:5. What is the ratio 2y:(x+6)?

A. 2:5
B. 3:5
C. 4:5
D. 5:3
E. 10:3

The OA is D.

Let:
x = 3n
y = 5n

3.6n / (5n+8) = 2/5

18n = 2*(5n+8)
n = 2.

So, x = 6, y = 10

2y:(x+6) = 20/12 = 5:3.

Please, can anyone explain another way to solve this PS question? Thanks in advance!
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by Jay@ManhattanReview » Mon May 07, 2018 7:53 pm
BTGmoderatorLU wrote:Ratio of two numbers x and y is 3:5. If x is increased by 20% and y is increased by 8 then the new ratio becomes 2:5. What is the ratio 2y:(x+6)?

A. 2:5
B. 3:5
C. 4:5
D. 5:3
E. 10:3

The OA is D.

Let:
x = 3n
y = 5n

3.6n / (5n+8) = 2/5

18n = 2*(5n+8)
n = 2.

So, x = 6, y = 10

2y:(x+6) = 20/12 = 5:3.

Please, can anyone explain another way to solve this PS question? Thanks in advance!
This is an efficient approach. All's good.

-Jay
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by Scott@TargetTestPrep » Wed May 09, 2018 3:57 pm
BTGmoderatorLU wrote:Ratio of two numbers x and y is 3:5. If x is increased by 20% and y is increased by 8 then the new ratio becomes 2:5. What is the ratio 2y:(x+6)?

A. 2:5
B. 3:5
C. 4:5
D. 5:3
E. 10:3
We are given that x/y = 3/5. So y = 5x/3. We can create the equation:

x(1.2)/(y + 8) = 2/5

Substituting 5x/3 for y, we have:

1.2x/(5x/3 + 8) = 2/5

5(1.2x) = 2(5x/3 + 8)

6x = 10x/3 + 16

18x = 10x + 48

8x = 48

x = 6

Since x = 6,then y = 5(6)/3 = 10. Thus, the ratio 2y:(x+6) is:

2(10)/(6 + 6) = 20/12 = 5/3

Answer: D

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