Is y=5?

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Re: Is y=5?

by Vemuri » Tue Mar 17, 2009 6:57 pm
jfranco23 wrote:If (x^3)(y^4)=5000, is y=5?

1. y is a positive integer
2. x is an integer
My answer is A.

Stmt1 : If y is a positive integer, x also has to be a positive integer to get 5000. The factors of 5000 are 2,2,2,5,5,5,5. So, x has to be 2 & y has to be 5. Sufficient.

Stmt 2 : If x is an integer, it could be positive or negative. So, y will be positive or negative based on x. So, cannot definitely answer the question. Insufficient.

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by cramya » Tue Mar 17, 2009 7:02 pm
Stmt I

y=10 x =cuberoot(1/2) no

x=2 y=5 yes

INSUFF

Stmt II

x=1 y= 4th root(5000) no

x=2 y =5 yes

INSUFF

Together

x integer
y integer

Only possible when x=2 y=5

SUFF

Choose C

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Re: Is y=5?

by KICKGMATASS123 » Tue Mar 17, 2009 7:44 pm
Vemuri wrote:
jfranco23 wrote:If (x^3)(y^4)=5000, is y=5?

St 1 is insuff

X can be a positive int even if y is negative.. since it has the power of 4. therefore, i dont think this fact is at all relevant. what's the OA?

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by Vemuri » Tue Mar 17, 2009 11:54 pm
cramya wrote:Stmt I

y=10 x =cuberoot(1/2) no

x=2 y=5 yes

INSUFF

Stmt II

x=1 y= 4th root(5000) no

x=2 y =5 yes

INSUFF

Together

x integer
y integer

Only possible when x=2 y=5

SUFF

Choose C
Aaaggghh....I missed it out completely. Thanks for correcting.

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by kheba » Wed Mar 18, 2009 12:56 am
Ans C.

Y being a positive integer is insufficient.

X being a positive integer is insufficient because y can be negative too.