At a garage sale, all of the prices of the items sold were different. If the price of a radio sold at the garage sale was both the 15th highest price and the 20th lowest price among the prices of the items sold, how many items were sold at the garage sale?
A. 33
B. 34
C. 35
D. 36
E. 37
The OA is B.
I get the solution as follow,
Price of radio is 15th highest and 20th lowest
Which means from top if you count price will be 15th and if you count from bottom the count will be 20th.
So, from top it is 15th and there are 19 more items below the list (As this is 20th from bottom).
Hence, 15 + 19 = 34.
So in all, there were 34 items sold at the garage.
Is there another strategic approach to solve this PS question? Can any experts help, please? Thanks!
A. 33
B. 34
C. 35
D. 36
E. 37
The OA is B.
I get the solution as follow,
Price of radio is 15th highest and 20th lowest
Which means from top if you count price will be 15th and if you count from bottom the count will be 20th.
So, from top it is 15th and there are 19 more items below the list (As this is 20th from bottom).
Hence, 15 + 19 = 34.
So in all, there were 34 items sold at the garage.
Is there another strategic approach to solve this PS question? Can any experts help, please? Thanks!





















