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by theachiever » Thu Nov 29, 2012 7:08 am
A rectangular box is 10 inches wide,10 inches long and 5 inches high.What is the greatest possible distance, in inches ,between any two points on the box?
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by Brent@GMATPrepNow » Thu Nov 29, 2012 7:20 am
theachiever wrote:A rectangular box is 10 inches wide,10 inches long and 5 inches high.What is the greatest possible distance, in inches ,between any two points on the box?
The greatest distance will be when the two points are in opposite corners.

In these instances, we have a nice rule that says:
If x, y, and z are the three measurements of a box, then the distance between two points in opposite corners equals sqrt(x^2 + y^2 + z^2)

So, for your question, the distance = sqrt(10^2 + 10^2 + 5^2) = sqrt(225) = 15

If you're interested, we have a free video that explains the above rule (via a practice question): https://www.gmatprepnow.com/module/gmat-geometry?id=869

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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