Want to clear this question:
Jar contains 3 green, 2 red and 3 blue balls. If we randomly pick 5 balls WITH replacement. What is the probability that of the 5 drawn balls picked 1 would be red, 2 green, and 2 blue balls?
My approach:
(5!/2!*2!)*(2/8*3/8*3/8*3/8*3/8)
AND:
Jar contains 3 green, 2 red and 3 blue balls. If we randomly pick 5 balls WITHOUT replacement. What is the probability that of the 5 drawn balls picked 1 would be red, 2 green, and 2 blue balls?
My approach:
(5!/2!*2!)*(2/8*3/7*2/6*3/5*2/4)
Is this correct?
Jar contains 3 green, 2 red and 3 blue balls. If we randomly pick 5 balls WITH replacement. What is the probability that of the 5 drawn balls picked 1 would be red, 2 green, and 2 blue balls?
My approach:
(5!/2!*2!)*(2/8*3/8*3/8*3/8*3/8)
AND:
Jar contains 3 green, 2 red and 3 blue balls. If we randomly pick 5 balls WITHOUT replacement. What is the probability that of the 5 drawn balls picked 1 would be red, 2 green, and 2 blue balls?
My approach:
(5!/2!*2!)*(2/8*3/7*2/6*3/5*2/4)
Is this correct?
