ahmedshafea wrote:What is the value of 2x/3y ?
(1) x^2/y^2 = 36/25
(2) x^5/y^5 > 1
Can some experts help me with this? How to come up with the correct answer?
Need thorough explanation regarding this one. Thanks
We have to get the value of 2x/3y.
2x/3y = (2/3)*(x/y).
So, if we get the UNIQUE value of x/y, we get the answer.
Question rephrased: What's the value of x/y?
Statement 1: x^2/y^2 = 36/25
(x/y)^2 = (6/5)^2
x/y = ±6/5
No unique value of x/y. Insufficient.
Statement 2: x^5/y^5 > 1
(x/y)^5 > 1
No unique value of x/y. Insufficient.
Statement 1 and 2:
From Statement 2, we get that (x/y)^5 > 1 => x/y > 1, thus, x/y is positive.
From Statement 1, we get that x/y = +6/5 or -6/5
Since -6/5 < 1, it is not a possible value of x/y.
Thus, x/y = 6/5. Sufficient.
The correct answer:
C
Hope this helps!
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