remainder of 1 when divided by 3

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uptowngirl92: Master | Next Rank: 500 Posts; Posts: 447; Joined: Sun Apr 19, 2009 9:08 pm; Location: Kolkata,India; Thanked: 7 times; GMAT Score:670

by uptowngirl92 » Sat Sep 19, 2009 1:27 am

How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3 ?
A. 15
B. 16
C. 17
D. 18
E. 19

[spoiler]Its 3k+1
k=0> 1
k=1>4
k=2>7
.
.
.
k=16>49
Therefore,should'nt the answer be 16?Please clarify.[/spoiler]

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Source: Beat The GMAT — Problem Solving | Sat Sep 19, 2009 1:27 am

mruzeful: Senior | Next Rank: 100 Posts; Posts: 58; Joined: Mon May 04, 2009 7:43 pm; Thanked: 1 times

by mruzeful » Sat Sep 19, 2009 2:15 am

you have used the method correctly but when u r counting,

3*0+1=1
3*1+1=4
..
3*16+1=49

u are taking the last '16' as the answer but u're not including the first '0' also into the count

so it should be 16+1=1

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