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The weights of four packages are 1, 3, 5, and 7 pounds, resp

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by BTGmoderatorDC » Mon Nov 26, 2018 10:36 pm

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Answers

A

B

C

D

E

Stats

Difficulty—

The weights of four packages are 1, 3, 5, and 7 pounds, respectively. Which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

a) 9

b) 10

c) 12

d) 13

e) 14

OA E

Source: Official Guide
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by Brent@GMATPrepNow » Tue Nov 27, 2018 6:51 am
BTGmoderatorDC wrote:The weights of four packages are 1, 3, 5, and 7 pounds, respectively. Which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

a) 9
b) 10
c) 12
d) 13
e) 14
For each answer choice, if we CAN create the total given weight, then we can ELIMINATE that answer choice.
a) 9 = 1 + 3 + 5 ELIMINATE
b) 10 = 3 + 7 ELIMINATE
c) 12 = 5 + 7 ELIMINATE
d) 13 = 1 + 5 + 7 ELIMINATE
By the process of elimination, the correct answer is E

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Brent
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by swerve » Tue Nov 27, 2018 9:51 am
The total weight of the four packages = 1 + 3 + 5 + 7 = 16 pounds. To get 14 pounds, we should remove a package of 2 pounds or two packages of 1 pound each. Neither is possible, thus the correct answer is 14 pounds, option E.
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by Brent@GMATPrepNow » Tue Nov 27, 2018 10:16 am
swerve wrote:The total weight of the four packages = 1 + 3 + 5 + 7 = 16 pounds. To get 14 pounds, we should remove a package of 2 pounds or two packages of 1 pound each. Neither is possible, thus the correct answer is 14 pounds, option E.
That's MUCH better than my solution!!

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by Scott@TargetTestPrep » Wed Mar 27, 2019 6:07 pm
BTGmoderatorDC wrote:The weights of four packages are 1, 3, 5, and 7 pounds, respectively. Which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

a) 9

b) 10

c) 12

d) 13

e) 14

OA E

Source: Official Guide

Let's examine each answer choice:

A) 9

1 + 3 + 5 = 9

B) 10

3 + 7 = 10

C) 12

5 + 7 = 12

D) 13

1 + 5 + 7 = 13

Since we eliminated every other choice, we know at this point that the answer is E. However, let's evaluate answer choice E for practice:

E) 14

We can see that 1 + 5 + 7 = 13 and 3 + 5 + 7 = 15, so it can't be 14.

Answer: E

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