pzazz12 wrote:A certain fruit stand sold apples for $0.70 each and bananas for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?
A. 10
B. 11
C. 12
D. 13
E. 15
Help me to solve it...............
How can we spend 630 cents if we can use only multiples of 70 and multiples of 50?
9*70 = 630, but all the answers are bigger than 9.
80+50 = 130, so let's try a multiple of 70 whose last 2 digits are 80 and a multiple of 50 whose last 2 digits are 50.
4*70 = 280.
630-280 = 350.
350/50 = 7.
So we could buy 4 apples for 70 cents each and 7 bananas for 50 cents each.
4+7 = 11.
The correct answer is B.
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