If f(x) + f(1-x)=10, then f(1/100)+f(2/100)+...+f(99/100) equals
A. 490
B. 495
C. 500
D. 505
E. 9900
A. 490
B. 495
C. 500
D. 505
E. 9900
f(1/100)+f(99/100)=10
f(2/100)+f(98/100)=10
...
Also since f(50/100)+f(50/100)=10, then f(50/100)=5
=> 10*(99-1)/2+5 = 495 => B
