evansbd wrote:I was checking some of the approaches here and possibly wasn't calculating the values correctly. I don't see how the sum of 141...145 = 10000.
Also, I focused on answers 11 and 153 through POE because I figured that if option E was both answers 5 and 77 then its probably not either since both can't be missing (only one page missing). However, assuming I could do this POE quickly, I had little confidence as to which of the remaining answers were correct.
Chase:
Could you show a calculation on how you found your range 141-143, then I could see how you eliminated 153 as an option.
Your POE is absolutely right, you can easily eliminate 153. The reason why stressed on 153 is because it is a trap answer. This is a trial and error kind of question. Therefore some people could reach to 142 as the choice and select 153 as the answer.
I found the range 141-143 (sorry it was a typo) on the following basis.
if you want to find out the sum of integers from 1 to 141 you calculate it through following method:
n/2[first term + last term]
n = no. of integers = 141 (141-1+1)
first term = 1
last term = 141
(141*142)/2 = 10011
Let me know if you still have any doubts.