A very fast solution is to see what happens when q = 1.if q is an odd number and the median of q consecutive integers is 120, what is the largest of these integers?
a) (q-1)/2 + 120
b) q/2 + 119
c) q/2 + 120
d) (q+119)/2
e) (q+120)/2
This means that there's only one integer in the set.
So, if the median of the set is 120, then the set is {120}, which means the greatest value in the set is 120
So the correct answer choice should yield 120 when q = 1.
a) (1-1)/2 + 120 = 120 PERFECT!
b) 1/2 + 119 = some non-integer
c) 1/2 + 120 = some non-integer
d) (1+119)/2 = 60
e) (1+120)/2 = some non-integer
Since only answer choice A yield the correct output, it is the answer.
Cheers,
Brent














