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GMAT Prep Similar Triangles

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by mals24 » Sun Nov 16, 2008 9:21 am
1/2SH = 2*1/2sh

SH = 2sh
S = 2sh/H--equ 1

Now since the triangles are similar: s/S = h/H
Substitute this in equ 1

S = 2 s*(s/S)
S^2=2s^s
S = sqrt2.s

Option C.
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by moneyman » Sun Nov 16, 2008 9:43 am
nice job
Maxx
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by cramya » Sun Nov 16, 2008 1:11 pm
Another property of similar triangles is

ratio of areas = square of ratio of sides

A-area of big trngle = 2a (given) S - SIDE
a - area of smaller trngl s - side

a / A = (s / S) ^ 2

a / 2a = s^2 / S^2

S = SQRT(2)s

C)
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