BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Sum of Integers

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 35
Joined: Tue Sep 09, 2008 10:12 pm
Location: Lko
Thanked: 3 times

by manulath » Sun Sep 28, 2008 9:22 am
C: 57

three consec number are to be divisible by 3

n, n+1, n+2
sum = 3n + 3 = which is divisible by 3
only 57 satisfies the req

...................................................
Top
Master | Next Rank: 500 Posts
Posts: 267
Joined: Wed Jul 16, 2008 12:20 am
Thanked: 4 times
Followed by:1 members

by Mani_mba » Sun Sep 28, 2008 9:37 am
IMO C.

The average of three consec nos (Sum/3) should be the second integer.

Only the third option is divisible by 3.

It is a good question. :)
Top
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Sun Sep 28, 2008 12:09 pm
The approach suggested by Manulath is the approach that needs to be used for these problems

x,x+1,x+2

x+x+1+x+2 = 3x+3 = 3 (x+1)

This shows that the sum must be a multiple of 3 and the only one that fits this condition is 57
Top
Post new topic Post Reply
• Page 1 of 1