ArunangsuSahu wrote:Find out how many numbers between 10^6 and 10^7 have the sum of their digits as 2?
Sum of digits of a number can be 2 only if either it is made of only one 2 and rest zeroes or two 1s and rest zeroes.
Number of such numbers between 1,000,000 and 10,000,000, i.e. such a seven digit number,
- 1. Two 1s and rest zeroes ---> Seven digit number starting with 1 and the other 1 can be in any other 6 places. Hence 6 such numbers.
2. One 2 and rest zeroes ---> Seven digit number starting with 2. Only one such number is possible.
Hence, total number of such integers in the given range = (6 + 1) = 7
The correct answer is B.
