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mgmat 4

by resilient » Wed May 21, 2008 4:13 pm
Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.
qa is a

would like to deal with this in charts and no ven diagrams please
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Source: — Data Sufficiency |
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by netigen » Wed May 21, 2008 11:31 pm
if you came across this one on MGMAT CAT then it means you are in the 700-800 range.

The stem of the question is tricky and can set you off easily.

Imp take from the question stem is that non veg non students = 15
1/2 Total Guest = veg

from A: veg student/veg non student = 2/3
non veg student/ non veg non student = 4/3

so, non veg students = 20

total non veg = 35
total veg = 35

total guest = 70

so A is sufficient

This may sound easy but when you get this in timed environment it can get tricky
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by cramya » Sun Nov 09, 2008 8:22 am
OA for this question is C by the way. Not A.
No C is not the OA. It is A. Please check again on your end[/spoiler]
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by praneeth » Sun Nov 09, 2008 11:03 am
cramya wrote:
OA for this question is C by the way. Not A.
No C is not the OA. It is A. Please check again on your end[/spoiler]
Yep, sorry I deleted post when I noticed but not in time I see.

Thank you.
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by kanha81 » Fri Mar 27, 2009 4:31 pm
netigen wrote:if you came across this one on MGMAT CAT then it means you are in the 700-800 range.

The stem of the question is tricky and can set you off easily.

Imp take from the question stem is that non veg non students = 15
1/2 Total Guest = veg

from A: veg student/veg non student = 2/3
non veg student/ non veg non student = 4/3

so, non veg students = 20

total non veg = 35
total veg = 35

total guest = 70

so A is sufficient

This may sound easy but when you get this in timed environment it can get tricky
Is there a better way to solve this problem? I am simply confused while trying to understand the solution. Any help is deeply appreciated. Thanks a bunch.
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