BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Problem solving OG 12. Experts please help me understand

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Tue Apr 26, 2011 3:28 am
by arpan307 » Thu Jun 23, 2011 5:31 am
If 4< (7-x)/3, which of the following must be true?

I. 5<x
II. |x+3| > 2
III. -(x+5) is positive


Options :
(A) II only
(B) III only
(C) I and II only
(D) II and III only
(E) I, II and III


The OA is D. I didn't get how to evaluate II condition. Experts kindly help on modulus.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Thu Jun 23, 2011 5:48 am
Hi,
if |y| < a then -a < y < a
if |y| > a then y < -a or y > a where a is a positive number
So, here is how we evaluate II
|x+3| > 2.
So, x+3 < -2 or x+3 > 2
So, x < -5 or x > -1
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Thu Feb 19, 2009 12:10 pmFollowed by: 2 members
Thanked: 3 times

by Bens4vcobra » Thu Jun 23, 2011 6:05 am
Frankenstein wrote:Hi,
if |y| < a then -a < y < a
if |y| > a then y < -a or y > a where a is a positive number
So, here is how we evaluate II
|x+3| > 2.
So, x+3 < -2 or x+3 > 2
So, x < -5 or x > -1
I understand II but I can't see how III must be true. Could you demonstrate?

If x < -5 from the given expression, then how is it that -(x+5)'must be positive?'
"It takes no ability to give effort. Toughness is not God-given; it's a choice. The discipline to execute is a habit." - Nick Saban
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Thu Jun 23, 2011 6:10 am
Bens4vcobra wrote: If x < -5 from the given expression, then how is it that -(x+5)'must be positive?'
Hi,
As you have reached to x < -5, I will continue from this
x < -5. So, x+5 < 0 right?
So, (x+5) is negative implies -(x+5) is positive.
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Thu Feb 19, 2009 12:10 pmFollowed by: 2 members
Thanked: 3 times

by Bens4vcobra » Thu Jun 23, 2011 6:13 am
Frankenstein wrote:
Bens4vcobra wrote: If x < -5 from the given expression, then how is it that -(x+5)'must be positive?'
Hi,
As you have reached to x < -5, I will continue from this
x < -5. So, x+5 < 0 right?
So, (x+5) is negative implies -(x+5) is positive.
Thanks very much. I just figured out my error before I read your post. I had a "duh" moment. It was right in front of my face.
"It takes no ability to give effort. Toughness is not God-given; it's a choice. The discipline to execute is a habit." - Nick Saban
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 407
Joined: Tue Jan 25, 2011 9:19 amFollowed by: 7 members
Thanked: 25 times

by Ozlemg » Thu Jun 23, 2011 12:32 pm
Thank you. Great explanation...
The more you suffer before the test, the less you will do so in the test! :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1