d^2=[(a1-a)^2+(a2-a)^2+....+(an-a)^2 ]/n
When we added 6 and 6, the numerator remained unchanged but the denominator
increased, so, the new deviation is less than d.
other way ( through negation technique)
choose the option one by one, assume the mean=average=6
1) -6, and 0 , since the sd is distance from the mean
-6 and 0 will increase the distance from the mean hence the data will more spreaded across the mean and hence sd will increase. ( so negate the option)
2)0 and 0 , since the sd is the distance from the mean .Here the SD will increase .
3)0 and 6 , the sd will increase, since sd is the distance from the mean
4)0 and 12, the sd will increase , since sd is the distance from the mean
5) 6, and 6 ,the sd will remain as it is; which means negligible data spread from the mean 6.
most of the time SD characteristics help to solve the question very quickly which might take more minutes when solving in any other way.
thanks,
surbhi