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Help!!!OG 11th edition, Q 208.

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by Nidhs » Fri Jan 11, 2008 4:12 pm
This is in reference to OG 11th edition, Q 208.
S is a set containing 9 different numbers. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
a) The mean of S is equal to the mean of T
b) The median of S is equal to the median of T
c) The range of S is equal to the range of T
d) The mean of S is greater than the mean of T
e) The range of S is greater than the range of T

Answer is E

However what if
S{-3,1,2,3,4,5,6,7,8}
T{1,2,3,4,5,6,7,8}

now the range os S equals 5 and that of T is 7, which is greater. So even (e) doesnt hold true. Now i don't know if my thought process is working correctly in this case. Please help!!
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by Stuart@KaplanGMAT » Fri Jan 11, 2008 7:30 pm
The range of S is 11, not 5.

Range is the distance between the largest and smallest numbers in the set. 8 - (-3) = 11

Should choice E actually read "The range of T is greater than the range of S"? The (E) you have listed is definitely not a "CANNOT BE TRUE" (since using your example, the range of S is 11 and the range of T is 7).

More likely, is the question "COULD BE TRUE"? Unless you've gotten the S and T backward, A, B, C and D are all impossible and fall into the "CANNOT BE TRUE" category.
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Thank you

by Nidhs » Fri Jan 11, 2008 7:48 pm
AHHH!!!!! THANK YOU:-D
I racked my brain for so loong over this. Silly me.
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by StarDust845 » Sat Jan 12, 2008 2:52 pm
Nidhs,

OA is D? No.

The correct option E in question is this:

E) The range of S is LESS than the range of T

Hence the answer is E.

Also Stuart I think you got it in the reverse Your stmt: "Unless you've gotten the S and T backward, A, B, C and D are all impossible "

Actually A,B C and D are all possible. Isn't it?

Calista.
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by Stuart@KaplanGMAT » Sun Jan 13, 2008 6:12 am
StarDust845 wrote:Nidhs,

Also Stuart I think you got it in the reverse Your stmt: "Unless you've gotten the S and T backward, A, B, C and D are all impossible "

Actually A,B C and D are all possible. Isn't it?

Calista.
Hmm.. I swear, some of those choices are different than the first time I read them! Must have been sleepy (unless the OP edited the post).

You're right - if we let:

S = {1, 2, 3, 4, 5, 6, 7, 8, 9}

and

T = {1, 2, 3, 4, 6, 7, 8, 9}

The sets will have the same median, mean and range.

If we let:

S = {1, 2, 3, 4, 5, 6, 7, 8, 9}

and

T = {1, 2, 3, 4, 5, 6, 7, 8}

S will have greater range than T.

With the rewording if E, it's impossible.
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Re: Help!!!OG 11th edition, Q 208.

by smushkas » Sun Jan 13, 2008 8:58 am
Nidhs wrote: a) The mean of S is equal to the mean of T
b) The median of S is equal to the median of T
c) The range of S is equal to the range of T
d) The mean of S is greater than the mean of T
e) The range of S is greater than the range of T


Hey there,
You made a mistake in the answer choice E, it should be "The range of S is LESS than the range of T" not greater. Then, it works fine.
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by Nidhs » Tue Jan 15, 2008 10:37 am
Yes...yes...big mistake!!!! My aplogies. Answer choice (E) reads
"The range of S is less than the range of T." I have been reading it wrong all this time.

I am so terribly sorry for the confusion.
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by gabriel » Tue Jan 15, 2008 11:36 am
Nidhs wrote:Yes...yes...big mistake!!!! My aplogies. Answer choice (E) reads
"The range of S is less than the range of T." I have been reading it wrong all this time.

I am so terribly sorry for the confusion.
Oooh .. 5 posts saying the same thing .. trying to be emphatic .. are we ?? :)
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