IMO E
St 1 says 14x^2=3
ie x^2 = 3/14
x = +-sq rt (3/14)---INSUFF
St 2 says y^2=1
y=+-1----INSUFF
Combining i & 2
If x and y have the same sign then xy>x^2*y^2
If x and y have opposite signs the xy<x^2*y^2
Hence the answer is E
exponents
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(E) ?
logic:
Is xy > x^2y^2?
(1) 14x^2 = 3
(2) y^2 = 1
-------------------------------
RHS => x^2y^2 = (x^2)^y^2 = (3/14)^sq(y) = 3/14 =.21
now, xy = x or -x (depending upon value of y)
now RHS is always greater than -x i.e. LHS < RHS
thus, LHS when, x =sqrt(3/14) =.41 i.e. LHS > RHS
thus, answer is both stmts not sufficient.
logic:
Is xy > x^2y^2?
(1) 14x^2 = 3
(2) y^2 = 1
-------------------------------
RHS => x^2y^2 = (x^2)^y^2 = (3/14)^sq(y) = 3/14 =.21
now, xy = x or -x (depending upon value of y)
now RHS is always greater than -x i.e. LHS < RHS
thus, LHS when, x =sqrt(3/14) =.41 i.e. LHS > RHS
thus, answer is both stmts not sufficient.












