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Source: — Problem Solving |

by theCodeToGMAT » Wed Oct 09, 2013 5:15 am
is the Answer [spoiler]{B}[/spoiler]?
Last edited by theCodeToGMAT on Wed Oct 09, 2013 5:22 am, edited 2 times in total.
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by [email protected] » Wed Oct 09, 2013 5:19 am
yes
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by prashanth.guru » Wed Oct 09, 2013 6:12 am
Can anyone explain this to me please....
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by Brent@GMATPrepNow » Wed Oct 09, 2013 6:20 am
[email protected] wrote:For some integer q, q² - 5 is divisible by all of the following EXCEPT
(A) 29
(B) 30
(C) 31
(D) 38
(E) 41
There's a nice rule that goes something like this:
If A is divisible by k, but B is not divisible by k, then A+B is NOT divisible by k, and A-B is NOT divisible by k.

There's another rule that says, "If there are n consecutive integers, then 1 of them is divisible by n"

Okay, now onto the question.

IMPORTANT: Notice that only answer choice B is divisible by 3. We'll use this fact in our solution.

Rewrite the given expression: q² - 5 = q² - 1 - 4 = (q - 1)(q + 1) - 4

NOTICE that (q - 1), q and (q + 1) are 3 consecutive integers, so one of them must be divisible by 3 (from the red rule above). So, let's consider 3 possible cases:

(q - 1) is divisible by 3
So, (q - 1)(q + 1) must also be divisible by 3
Since 4 is NOT divisible by 3, we know that (q - 1)(q + 1) - 4 is NOT divisible by 3 (from the green rule above)
If (q - 1)(q + 1) - 4 is not divisible by 3, it CANNOT be divisible by 30

q is divisible by 3
So, q² must also be divisible by 3
Since 5 is NOT divisible by 3, we know that q² - 5 is NOT divisible by 3 (from the green rule above)
If q² - 5 is not divisible by 3, then it CANNOT be divisible by 30

(q + 1) is divisible by 3
So, (q - 1)(q + 1) must also be divisible by 3
Since 4 is NOT divisible by 3, we know that (q - 1)(q + 1) - 4 is NOT divisible by 3 (from the green rule above)
If (q - 1)(q + 1) - 4 is not divisible by 3, it CANNOT be divisible by 30

Now that we've examined all 3 possible cases, we can conclude that q² - 5 CANNOT be divisible by 30

Answer = B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by vinay1983 » Wed Oct 09, 2013 6:35 am
Breant i liked the "rule" there, but i feel it is waay lengthy to solve the question this way. Any practical or common sense approach here?

Thanks
You can, for example never foretell what any one man will do, but you can say with precision what an average number will be up to!
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by Brent@GMATPrepNow » Wed Oct 09, 2013 6:53 am
vinay1983 wrote:Breant i liked the "rule" there, but i feel it is waay lengthy to solve the question this way. Any practical or common sense approach here?

Thanks
The only other approach I can think of (at the moment) is plugging in numbers and slowly eliminating answer choices.

q = 6: q² - 5 = 31 ELIMINATE C
q = 7: q² - 5 = 44
q = 8: q² - 5 = 59
q = 9: q² - 5 = 76 = (2)(38) ELIMINATE D
q = 10: q² - 5 = 95
q = 11: q² - 5 = 116 = (4)(29) ELIMINATE A
q = 12: q² - 5 = 139
q = 13: q² - 5 = 164 = (4)(41) ELIMINATE E
STOP

The correct answer must be B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by GMATGuruNY » Wed Oct 09, 2013 6:56 am
[email protected] wrote:For some integer q, q^2 - 5 is divisible by all of the following EXCEPT
(A) 29
(B) 30
(C) 31
(D) 38
(E) 41
If you don't see an elegant solution to a GMAT problem, try solving by BRUTE FORCE.
Here, any answer choice that can divide into q² - 5 can be eliminated.
To find these four incorrect answer choices, plug in increasing integer values for q:

If q=6, then q² - 5 = 31. Eliminate C.
If q=7, then q² - 5 = 44.
If q=8, then q² - 5 = 59.
If q=9, then q² - 5 = 76 = 2*38. Eliminate D.
If q=10, then q² - 5 = 95 = 5*19.
If q=11, then q² - 5 = 116 = 4*29. Eliminate A.
If q=12, then q² - 5 = 139.
If q=13, then q² - 5 = 164 = 4*41. Eliminate E.

The correct answer is B.

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