Please complete the quetion. is an integer?venmic wrote:If m and n are positive integers, is an integer?
(1)sqroot(m) is an integer.
(2)sqroot(n) is an integer.
can someone explain
OG12 diagnostic QS 44
This topic has expert replies
Source: Beat The GMAT — Problem Solving |
GMAT/MBA Expert
- Rahul@gurome
- GMAT Instructor
- Posts: 1179
- Joined: Sun Apr 11, 2010 9:07 pm
- Location: Milpitas, CA
- Thanked: 447 times
- Followed by:88 members
I think you are missing some expression in the question, can you please check?venmic wrote:If m and n are positive integers, is an integer?
(1)sqroot(m) is an integer.
(2)sqroot(n) is an integer.
can someone explain
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
- Patrick_GMATFix
- GMAT Instructor
- Posts: 1052
- Joined: Fri May 21, 2010 1:30 am
- Thanked: 335 times
- Followed by:98 members
OG 12 Diagnostic #44 is:
If m and n are positive integers, is [sqrt(m)]^n an integer?
(1) sqrt(m) is an integer
(2) sqrt(n) is an integer
---------------------------------
hi Venmic,
The 1st statement is sufficient because it tells us that the base of the question stem is an integer, so [sqrt(m)]^n is an integer^n. The result will always be an integer (because n is an integer).
The 2nd statement is not sufficient because although it guarantees that n itself is an integer (a perfect square), the base of the question stem could be an integer (which would make the whole expression an integer) or a weird decimal.
The answer is A. A fuller explanation is attached along with take-away lesson from the OG 12 Companion. Those who cannot see the attachment can read it here.
If you have trouble with this type of problems, practice similar questions by setting topic='Number Properties & Exponents & Roots' and difficulty='500-600' in the Drill Generator
-Patrick
If m and n are positive integers, is [sqrt(m)]^n an integer?
(1) sqrt(m) is an integer
(2) sqrt(n) is an integer
---------------------------------
hi Venmic,
The 1st statement is sufficient because it tells us that the base of the question stem is an integer, so [sqrt(m)]^n is an integer^n. The result will always be an integer (because n is an integer).
The 2nd statement is not sufficient because although it guarantees that n itself is an integer (a perfect square), the base of the question stem could be an integer (which would make the whole expression an integer) or a weird decimal.
The answer is A. A fuller explanation is attached along with take-away lesson from the OG 12 Companion. Those who cannot see the attachment can read it here.
If you have trouble with this type of problems, practice similar questions by setting topic='Number Properties & Exponents & Roots' and difficulty='500-600' in the Drill Generator
-Patrick
- Attachments
-
- OG12 Companion-T044.pdf
- (70.76 KiB) Downloaded 80 times
- Check out my site: GMATFix.com
- To prep my students I use this tool >> (screenshots, video)
- Ask me about tutoring.













