Doubts

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Doubts

by ruchisharma » Thu Aug 12, 2010 3:58 am
I) If ab is not equal to zero, and points (-a,b) and (-b,a) are in the same quadrant of the xy-plane, is point (-x,y) in this same quadrant?

(1) xy>0
(2) ax>0

correct answer:C

II)The numbers x and y are not integers. The value of x is closest to which integer?

(1) 4 is the integer that is closest to x+y.
(2) 1 is the integer that is closest to x-y.

correct answer:E

III) Is 2x-3y < x^2 ?



(1) 2x-3y = -2
(2) x>2 and y>0

Correct answer: D

IV) Working alone at its constant rate, a machine seals k cartons in 8 hours, and working alone at its own constant rate, a second machine seals k cartons in 4 hours. If the two machines, each working at its own constant rate and for the same period of time, together sealed a certain number of cartons, what percent of the cartons were sealed by the machine working at the faster rate?

a) 25%
b) 100/3 %
c) 50%
d) 200/3%
e) 75%

Correct answer : D

V) Circular gears P & Q start rotating at the same time at constant speeds. Gear P makes 10 revolutions per minute, and gear Q makes 40 revolutions per minute. How many seconds after the gears start rotating will gear Q have made exactly 6 more revolutions than gear p?

a) 6
b) 8
c) 10
d) 12
e) 15

VI) A certain roller coaster had 3 cars, and a passenger is equally to ride in any 1 od the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

a) 0
b) 1/9
c) 2/9
d) 1/3
e) 1

Correct answer :C
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by Rahul@gurome » Thu Aug 12, 2010 4:21 am
Ruchi, please post only one question in one thread.

Question 1:

If ab is not equal to zero, and points (-a,b) and (-b,a) are in the same quadrant of the xy-plane, is point (-x,y) in this same quadrant?

(1) xy>0
(2) ax>0

Solution:

(1) xy > 0 implies both x & y should be both positive or both of them should be negative. So it cannot be said whether (-x, y) will lie in same quadrant or not.
a and b can be both positive and x and y can be both negative.

So, (1) is NOT SUFFICIENT.

2) ax > 0 implies both a & b should be both positive and x and y should be both negative. But nothing is said about the sign of y.
a and b can be both positive and x and y can be both negative.

So, (2) is NOT SUFFICIENT.

Combining (1) & (2), if a and x are both positive, then as x is positive y has to be positive to satisfy condition in statement (1). Since a is positive so b is also positive.
Similarly when a and x are negative, then y will also be negative to satisfy xy > 0. Since a is negative so b is also negative.
So, combining the statements we can answer the question.

The correct answer is [spoiler](C)[/spoiler].
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by kmittal82 » Thu Aug 12, 2010 4:33 am
Question 3:

1) 2x - 3y = -2

So the question stem is effectively asking:

Is x^2 > -2

Square of any number must be >= 0, hence this is sufficient

2) Rearrange the equation from the stem

Is x^2 - 2x + 3y > 0 ?

=> x(x-2) + 3y > 0 ?

If x>2 and y>0, the above will always be true (always positive and not greater than 0), hence this is sufficient as well

Both statements alone are sufficient, hence (D)

Question 4:

This can be solved by simple logic.

One machine is twice as fast as the other.
If machine 1 does 1 unit of work, machine 2 can do 2 units of the work in the same time
Total work done together = 3 units
Work done by machine 2 = 2 units

Therefore, amount of work done by machine 2 = 2/ 3 = 66.6%

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by kmittal82 » Thu Aug 12, 2010 4:40 am
Question 5:

P makes 1/6 revs/second
Q makes 4/6 = 2/3 revs /second

Thus, after 1 second, Q has made 2/3 - 1/6 = 1/2 revs more than than P

So, 1/2 revs in 1 second, therefore to make 6 more revs, time taken to 12 seconds (D)

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by Rahul@gurome » Thu Aug 12, 2010 4:49 am
Question 2:
The numbers x and y are not integers. The value of x is closest to which integer?

(1) 4 is the integer that is closest to x+y.
(2) 1 is the integer that is closest to x-y.

Solution:

(1) This implies that 3.5 <= x+ y < 4.5 There can be more than one value for x and y in this case. So, no unique answer.

Hence, (1) is NOT SUFFICIENT to answer the question.

(2) This implies that 0.5 <= x - y < 1.5. There can be more than one value for x and y in this case. Again, no unique answer.

Hence, (2) is NOT SUFFICIENT to answer the question.

Combining (1) and (2), 4 <= 2x < 6 or 2 <= x < 3, which implies 2 and 3 both are the closest integers. Not a unique answer.

The correct answer is [spoiler](E)[/spoiler].
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by Prashantbhardwaj » Sat Aug 14, 2010 9:06 am
Question VI)

Its a permutation and combination question.

The passenger has three choices for each ride and the same choice can be repeated choices.
Hence total no of permutations for three rides are

3*3*3= 27

However in the question we are to find the probability of cases in which he sits in one car only once for each of the three turns Hence we are to find the permutations for the passenger sitting in a different car each time when he takes a ride (i.e. repetitions are not allowed) therefore total no of permutations for this are:
P(3,3) = 3! = 6

And so the probability is 6/27 or 2/9.

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by Prashantbhardwaj » Sat Aug 14, 2010 9:06 am
Question VI)

Its a permutation and combination question.

The passenger has three choices for each ride and the same choice can be repeated choices.
Hence total no of permutations for three rides are

3*3*3= 27

However in the question we are to find the probability of cases in which he sits in one car only once for each of the three turns Hence we are to find the permutations for the passenger sitting in a different car each time when he takes a ride (i.e. repetitions are not allowed) therefore total no of permutations for this are:
P(3,3) = 3! = 6

And so the probability is 6/27 or 2/9.