1) Examples we can choose here: 2 and 3.
if k = 2.
20*2 = 40 is divisible by 8 possible numbers. 2^3*5^1 = (4)(2) = 8.
if k = 3.
20*3 = 60
60 is divisible by 12 possible numbers. 2^2*3*5 = (3)(2)(2) = 12.
Insufficient.
2) k = 7
20*7 = 140
140 is divisible by 12 factors. 2^2*5*7 = (3)(2)(2) = 12. Sufficient.
IMO B.
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Good call, ssmiles08. I thought it was D until I read what you said about K being 2 or 3. I now am 100% behind ssmiles08's answer.
















