What is the greatest integer \(k\) for which \(32.45\cdot\)

This topic has expert replies
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3008
Joined: Mon Aug 22, 2016 6:19 am
Location: Grand Central / New York
Thanked: 470 times
Followed by:34 members

by Jay@ManhattanReview » Thu Sep 19, 2019 9:11 pm
swerve wrote:What is the greatest integer \(k\) for which \(32.45\cdot 10^{k}\) is less than 1?

A. -2
B. -1
C. 0
D. 1
E. 2

The OA is A

Source: GMAT Prep
For 32.45 x 10^k to be less than 1, we need to move the decimal between 2 and 4 two places to the left. For that to happen, we must at least divide 32.45 by 100. Thus, the greatest integer value of k would be -2.

The correct answer: A

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: GMAT Classes Munich | GMAT Prep Courses Kuala Lumpur | LSAT Prep Courses DC | SAT Prep Classes Boston | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8086
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

by Scott@TargetTestPrep » Tue Sep 24, 2019 10:21 am
swerve wrote:What is the greatest integer \(k\) for which \(32.45\cdot 10^{k}\) is less than 1?

A. -2
B. -1
C. 0
D. 1
E. 2

The OA is A

Source: GMAT Prep

Since 0.3245 is less than one, the largest possible value of k is -2 since 32.45 x 10^-2 = 0.3245.

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage