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by adi_800 » Fri Oct 14, 2011 12:07 am
3 spherical chocolates are packed in a straight line in a rectangular box that encloses them flush on all sides. If the volume of each of the chocolates is increased by 50% and they are placed in a similar fashion in a new box, what is the ratio of the volume of the new box to that of the original box?

A. 2
B. 3/2
C. pi*(sqrt(2/3)
D. (3/2)^1/3
E. 3/2 (sqrt2)
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by adi_800 » Fri Oct 14, 2011 12:07 am
OA B
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by shankar.ashwin » Fri Oct 14, 2011 12:21 am
Since its a ratio between 2 quantities, 3 spheres or 1 sphere would not make a difference.

Vol of Sphere = r^3 (Pi and 4/3 are constants and would get canclled)
Vol of bigger sphere = 3/2* r ^3 (50% bigger is 3/2)

You are asked ratio of bigger to smaller, which is 3/2 B IMO

Vol of the box would be l*b*h all of which are proportional to 'r', imagine a single sphere enclosed by a cube.
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