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mgmat-tough one probability

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by pradeepkaushal9518 » Fri Jul 16, 2010 4:04 am
Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?

5/6
2/3
1/2
5/12
1/3
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Source: — Problem Solving |

by kvcpk » Fri Jul 16, 2010 4:14 am
pradeepkaushal9518 wrote:Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?

5/6
2/3
1/2
5/12
1/3
There are only 2 players. There are three possiibilities
Jim wins
Renee wins.
Tie.

Hence probabaility is 1/3

pick E
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by ryantherocket » Fri Jul 16, 2010 5:45 am
Another way to look at it is: Whatever Renee picked, there is only 1 out of 3 choices that will result in Jim's victory. So probability that Jim picks the correct choice is 1/3
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