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dandillion
- Newbie | Next Rank: 10 Posts
- Posts: 9
- Joined: Sat Jul 26, 2008 2:04 pm
first off, it doesn't really matter how many numbers are in the sets, because the range of the sets is what matters.
before looking at the statements, think about the possibilities for the individual sets:
* there's no minimum range necessary for either set; in fact, the individual sets can even have a range of zero, and still produce as large a combined range as you want.
for instance, set A could consist of twenty copies of the number 0, and set B could consist of forty copies of the number 100. in this case, each of the sets has a range of 0, but the combined range is 100.
* there's also no maximum range necessary, especially because there are no upper bounds imposed on the range of anything in the problem.
therefore, even if you combine the two statements:
* the range of set B could be really small. for instance, if set A is twenty 0's, and set B is twenty 99's and twenty 100's, then both conditions are satisfied, but the range of set B is only 1.
* the range of set B could also be huge. for instance, set A could range from 0-100, and set B could range from 100-1000. in that case, the range of set B is 900.
answer = e
