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OG2015 PS Running at the same

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OG2015 PS Running at the same

by lionsshare » Fri Sep 08, 2017 3:40 pm
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

OA: B

Can someone please explain how to solve this problem. Thank you.
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by Jay@ManhattanReview » Fri Sep 08, 2017 10:37 pm
lionsshare wrote:Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800

OA: B

Can someone please explain how to solve this problem. Thank you.
Given: 6 identical machines can produce a total of 270 bottles/minute

=> 10 identical machines can produce a total of 270*(10/6) = 450 bottles/minute

=> 10 identical machines can produce a total of 450*4 = 1800 bottles in 4 minutes

The correct answer: B

Hope this helps!

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by [email protected] » Sat Sep 09, 2017 10:05 am
Hi lionsshare,

We're told that 6 identical machines can produce a total of 270 bottles per minute. We're asked for the number of bottles that 10 such machines would produce in 4 minutes when working at this same rate.

Since this is just a big 'rate' question, you can approach the math in a couple of different ways. From the information in the first sentence, since 6 divides evenly into 270, you could figure out the rate/minute for 1 machine...

270/6 = 45 bottles/minute for 1 machine

Since we have 10 machines working for 4 minutes each, that would give us...

(10)(4)(45) = 1800 bottles

Final Answer: B

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by Scott@TargetTestPrep » Tue Mar 27, 2018 10:41 am
lionsshare wrote:Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

(A) 648
(B) 1,800
(C) 2,700
(D) 10,800
(E) 64,800
We can create the following proportion, where x = the number of bottles 10 machines can produce in a minute:

6/270 = 10/x

6x = 2700

x = 450

Thus we see that 10 machines can produce 450 bottles per minute and thus they can produce 450 x 4 = 1,800 bottles in 4 minutes.

Answer: B

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by rishab0507 » Sat Sep 07, 2019 10:02 am
6 machines produce = 270 bottles/ min
1 min can produce : 270/ 6 bottles / min
i.,e 45 bottles / min

Now 10 machines can produce how many bottles / min
10 * 45 = 450 bottles/ min
in 4 min 10 machines can produce : 450*4 = 1800 bottles
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