-
guerrero
- Master | Next Rank: 500 Posts
- Posts: 227
- Joined: Sun Apr 08, 2012 4:53 am
- Thanked: 12 times
- Followed by:3 members
Hi All ,
Pipes A and B can fill a cistern in 20 and 30 minutes and C can empty it in 15 minutes. If the three are opened and closed one after the other successively for 1 min. each in that order, how soon will the cistern be filled ?
1)180 min
2)160 min
3)167 min
4)187 min
I could calculate part filled in 3 mins = 1/60th Part .
part filled in 177 min = 59/60th
remaining part = 1- 59/60 = i/60
i am stuck after this step . Please help me understand the approach .
thanks in advance !
Pipes A and B can fill a cistern in 20 and 30 minutes and C can empty it in 15 minutes. If the three are opened and closed one after the other successively for 1 min. each in that order, how soon will the cistern be filled ?
1)180 min
2)160 min
3)167 min
4)187 min
I could calculate part filled in 3 mins = 1/60th Part .
part filled in 177 min = 59/60th
remaining part = 1- 59/60 = i/60
i am stuck after this step . Please help me understand the approach .
thanks in advance !












