BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 28
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

15 live classes from Sep 28, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Weighted Average

Expert replies
by logitech » Thu Jan 15, 2009 11:17 pm
A weighted average multiplies each data point by an arbitrary 'weight' and divides by the sum of the weights. Your everyday garden variety average, or arithmetic mean, is actually a special case of a weighted average, except all the weights are equal to 1.
X= 4

Y = 8

AV = 6

4---6---8

Notice the distance to average from both sides are the SAME (2)

Now let's find the average of 4, 4, 4, 8

AV = 20/4=5

4..5........8

Now if you notice the distance between 4 and AVERAGE is 1 and the distance between 8 and AVERAGE is 3

since we used 3 fours our average shifted close to the 4.

if you compare the distances

4...L...5....3L.....8

L/3L = 1/3 gives us the weights of the each term in a reverse proportion:

from this distance information you can conclude

3 fours
1 eight

Play around with this concept and you will find it very useful in many mixture and average questions.

Happy studying,
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Join the discussion
Source: — Data Sufficiency |

by logitech » Thu Jan 15, 2009 11:18 pm
Stuart Kovinsky wrote:
dferm wrote:During a sale, a clothing store sold each shirt at a price of $15 and each sweater at a price of $25. Did the store sell more sweaters than shirts during the sale?

(1) The average (arithmetic mean) of the prices of all the shirts and sweaters that the store sold during the sale was $21.

(2) The total of the prices of all the shirts and sweaters that the store sold during the sale was $420

Please explain..

Thanks.
This question is much simpler if we think of concepts rather than specific arithmetic.

(1) Well, $21 is closer to $25 than it is to $15. Therefore, $25 must have more "weight" in the weighted average equation. The only way that $25 could have more weight is if there were more items sold at $25 than at $15: sufficient.

(2) We still have too many variables (2) and not enough equations (1): insufficient.

(1) is sufficient and (2) isn't: choose (A).
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Join the discussion

by yalanand » Thu Jan 15, 2009 11:23 pm
thank you logi.....
Join the discussion

by nitinrai » Thu Jan 15, 2009 11:39 pm
Great Advice Man!!!
After Stacey .... I really like reading your stuff .. If Stacey is GMAT Queen then you are definately Gmat king .. (atleast for Quant L:))
I firmly believe that one can succeed at almost anything for which one has unlimited enthusiasm.
Join the discussion