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MGMAT DS

by ankurmit » Tue Aug 10, 2010 2:47 am
Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.
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Source: — Data Sufficiency |
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by kvcpk » Tue Aug 10, 2010 3:08 am
ankurmit wrote:Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.

D = 3
stmt1:
3/TW = 4
TW = 3/4
No info about Bob's speed or time .. Hence INSUFF

stmt2:
SB = SW+1
No speeds are given in number. Hence time cant be calculated. INSUFF

Combining:
TW = 3/4 = 45 mins
SB = SW+1
SB = 4+1 = 5
Therefore, TB = 3/5 = 36 mins
Total time taken by B was 36 + 30 = 66 mins
Hence Wendy had to wait 66-45 = 21 mins.
(Calculation not needed)

pick C

However, I do not like the problem Because, it doesnt tell from where Bob started. We need to assume that he started from Home to restaurant. Are you sure that this is MGMAT's?
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by ankurmit » Tue Aug 10, 2010 3:23 am
ya ...u are right..Its MGMAT quistion.

yesterday only i took test and got 650 in MGMAT.

Dear can you guide me if you have an idea hows this score.
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by arora007 » Wed Aug 11, 2010 8:51 am
ankurmit wrote:Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.

the solution to this DS is verbal calculations....see....

Wendy walked at 4 miles per hour..... BOB could have walked at 100 miles per hour or 1 mile per hour... so... there could be a time lag or a time lead...one does not know... so 1 is insufficient....

Wendy walks at 100 miles per hour and Bob 101 miles per hour....so Wendy has already reached even before Bob could start....
or
Wendy walk at 1 mile per hour and Bob at 2 miles per hour.... i.e. Bob reaches before Wendy...


try practice some questions verbally.... this will train your brain to think more mathematically....
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