BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

repeated factors question

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 62
Joined: Mon May 21, 2007 12:00 am

repeated factors question

by vanesslondon » Thu Nov 13, 2008 5:54 am
Could someone pls expalin the following to me?
If j is divisible by 12 and 10 is j divisible by 24?
I can't understand why the answer is maybe rather than a definitive yes. It relates to repeated factors... could somebody please explain? thank you!
Top
Source: — Quantitative Reasoning |
User avatar
Legendary Member
Posts: 519
Joined: Sat Jan 27, 2007 7:56 am
Location: India
Thanked: 31 times

by Neo2000 » Thu Nov 13, 2008 7:43 am
What is the least value that J can have to be divisible both by 12 and 10?
Obviously, the LCM of 10 and 12 which is 60
Is 60 divisible by 24? No.

What is the next number after 60 that is divisible by 12 and 10?? 120
Is 120 divisible by 24? Yes

So what is the value of J? 60 or 120? We dont know. Thus the answer is a "Maybe"
Top
Senior | Next Rank: 100 Posts
Posts: 62
Joined: Mon May 21, 2007 12:00 am

by vanesslondon » Thu Nov 13, 2008 2:08 pm
Thank you very much, but I am still not sure I understand this fully: why can' t I reduce 12 and 10 to their prime factors and see whether by multiplying these I can get 24? If I do this, the prime numbers I get are 2, 2, 2, 3, 5, though I know (by looking at the answer) that this is one 2 too many. Why is this, and what method should I use for these sorts of questions in future? I know this has somethng to do with repeated primes...

Thanks again!
Top
User avatar
Legendary Member
Posts: 519
Joined: Sat Jan 27, 2007 7:56 am
Location: India
Thanked: 31 times

by Neo2000 » Thu Nov 13, 2008 2:15 pm
You are confusing concepts over here.

The concept of "repeated prime" is useful when you want to find the LCM of 2 or more numbers

When you split numbers into their prime factors, the shortest way to finding their LCM is to take the primes that have the highest powers
12 = 2x2x3 = (2^2) x 3
10 = 2x5

In the above case, the highest power of 2 is 2^2 so you consider 2^2. 3 and 5 only have a power of 1
So your LCM = 2^2 x 3 x 5 = 60
Top
Senior | Next Rank: 100 Posts
Posts: 62
Joined: Mon May 21, 2007 12:00 am

by vanesslondon » Fri Nov 14, 2008 1:12 am
Thanks so so much - that is really helpful. Got it! :)
Top
Post new topic Post Reply
• Page 1 of 1