MGMAT Formulas - GP

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MGMAT Formulas - GP

by vineetbatra » Fri Mar 05, 2010 7:44 am
Hello,

I see a question in the MGMAT book and not completly sure about one part of the solution.

In sequence Cn, we are given that C3 = 12 and C5 = 3. If each term is = the previous term times a constant number, what is the value of C10

using the formula A1*q^(n-1), where A1 is the first number, q is the constant multiplier and n = number in the sequence.

Joining C3 and C5 I get q^2 = 1/4, so Q = +1/2 or -1/2 and A1 = 48. The book says we need not consider -1/2. The answer for C10 is 3/32, but if I consider -1/2 then 48 * (-1/2)^(10-1), I get -3/32.

Can some one explain why can't we use -1/2.
Source: — Data Sufficiency |

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by kstv » Fri Mar 05, 2010 8:59 am
The sign of the expression will keep alternating if u multiply by the constant -1/2.

C3 = 12 C4 = 12*-1/2 = -6 C5 = -6*-1/2 = +3 so on
Cn > 0 is n is odd and < 0 if n is even.

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by vineetbatra » Fri Mar 05, 2010 9:01 am
So what will be the value for C10? -3/32? book says its 3/32.