BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Let M be the maximum value and N be the minimum value of the

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
User avatar
Master | Next Rank: 500 Posts
Posts: 142
Joined: Sat Feb 20, 2010 7:23 pm
Thanked: 8 times
Followed by:1 members

by bpgen » Sat Mar 06, 2010 4:55 am
M-N would be b^2/c - a^2/d,
so values of a,b,c,d would be required to determine value of 'M-N'
therefore IMO it is C, BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
"Ambition is the path to success. Persistence is the vehicle you arrive in."
Top
Legendary Member
Posts: 610
Joined: Fri Jan 15, 2010 12:33 am
Thanked: 47 times
Followed by:2 members

by kstv » Sat Mar 06, 2010 5:47 am
M or N = x²/y+1 and we have to assume M and N have to +ve
M = { (a<=x<=b)²/c<=y<=d } +1 just knowing c = 3 tells us nothing . Insufficient.
so take (2) seperately
The expression (a<=x<=b)² should be maximum and y should be minimun, both having the same + ve
x² will be +ve so y cannot be -ve to get the max value
x can be -ve or +ve, so |x|= b = 5 is the maximum value , suppose it was -7 then that value should be taken
y has to be the least +ve value , that is c= 1
M = 25+1 = 26
N = x²/y+1 , x² should take the minumum value, so x =+or - 1, |x|=1
y should the highest value possible which is d =7 the value of c = 3 is not needed.
so N = 1/7 + 1

I still feel too many assumptions to be made for B to be the correct option.
Top
Post new topic Post Reply
• Page 1 of 1